Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil age. After further 8 years, how many times would he be of Sunil age?

A. 4 times

B. 4 times

C. 2 times

D. 3 times

• Assume that Sunil's present age = x.
  
  Then father's present age = 3x + x = 4x
  
  
  
  After 8 years, fathers age = 2 ½ times of Sunils' age
  
  => (4x+8) = 2 ½ × (x+8)
  
  => 4x + 8 = (5/2) ×(x + 8)
  
  => 8x + 16 = 5x+ 40
  
  => 3x = 40-16 = 24
  
  => x = 24/3 = 8
  
  
  
  After further 8 years,
  
  Sunil's age = x + 8+ 8 = 8+8+8 = 24
  
  Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48
  
  Father's age/Sunil's age = 48/24 = 2
  
• 9 years agoHelpfull: Yes(15) No(1)
• let sunils s present age be x years. Then, father's present age =(x + 3x) years = 4x years.
  
  (4x + 8) = 5/2 (x + 8)
  
  8x + 16 = 5x + 40
  
  3x = 24
  
  x = 8.
  
  Hence, required ratio =(4x+16/x+16)=48/24
  ans=2 times
  
  
• 8 years agoHelpfull: Yes(3) No(0)
• 32 question no from rs.agarwal book from age topic
  
• 9 years agoHelpfull: Yes(1) No(0)
• none of these.
  ans is : 11/5 times.
  
• 9 years agoHelpfull: Yes(1) No(7)
• father`s present age = x(let) and sunil`s present age = y
  ATQ, x = 3y + y
  after 8 yrs, x +8 = 5/ 2 (y+8)
  calculating , y = 8 and x = 32 which are present age of sunil and his father
  after further 8 years, sunil = 8 +8+ 8 = 24
  father = 322 +8 +8 = 48
  thus father will 2 times of sunil`s age
  C. 2 times
• 9 years agoHelpfull: Yes(1) No(0)
• multiple choices are available.
• 10 years agoHelpfull: Yes(0) No(0)
• plz send me....ayshu.530@gmail.com
  
• 10 years agoHelpfull: Yes(0) No(2)