In how many ways can 11 identical books on English and 9 identical books on Maths be placed in a row on a shelf so that two books on Maths may not be together?

• first simply place the 9 maths books on shelf.
  So, ways to place 9 identical books of maths=9/9=1
  
  now remaining space where 11 identical books on English be placed=10 spaces
  
  now,ways to place 1st English books in 10 positions=10
  ways to place 2nd English books in 10 positions=10
  .
  .
  . therefore, total ways to place 11 English book=[10^11]/11
  
  total ways=[10^11]/11
  
  
• 10 years agoHelpfull: Yes(0) No(0)