There are 16 people, they divide in to four groups,now from those four groups select a team of three members,such that no two members in the team should belong to same group

• 4c1*4c1*4c1*4c3=256 (4c3 means we can select any 3 teams from four teams and each one from each team)
• 10 years agoHelpfull: Yes(43) No(0)
• let there is 4 team A , B , C, D, having 4 member each.
  now total number of team can be formed is A B C OR A B D OR A C D OR B C D .
  SO for first team 1 member selected from group A by 4c1 ways , similarly 1 member from B by 4c1 ways , similarly from C by 4c1 ways.
  so we can select 1st team by 4c1 * 4c1 *4c1 *4c1
  since we can select team as ABC OR ABD OR ACD OR BCD SO no of ways of selecting team is
  (4c1 * 4c1 *4c1 *4c1 ) OR (4c1 * 4c1 *4c1 *4c1 ) or (4c1 * 4c1 *4c1 *4c1 ) OR (4c1 * 4c1 *4c1 *4c1 )=
  
  (4c1 * 4c1 *4c1 *4c1 ) + (4c1 * 4c1 *4c1 *4c1 ) + (4c1 * 4c1 *4c1 *4c1 ) + (4c1 * 4c1 *4c1 *4c1 ) =
  64+64+64+64 = 256
• 10 years agoHelpfull: Yes(14) No(8)
• (4c1*4c1*4c1)+(4c1*4c1*4c1)+(4c1*4c1*4c1)+(4c1*4c1*4c1)
  4*(4c1*4c1*4c1)
  4*(4*4*4)
  =256
• 10 years agoHelpfull: Yes(13) No(1)
• @Rohit Raj 4c0=1 then how can you get 4^4
  
• 10 years agoHelpfull: Yes(7) No(0)
• 4c1*4c1*4c1*4c0=4^4=256
  select one one from three groups by 4c1 and 0 from last group by 4c0.
• 10 years agoHelpfull: Yes(6) No(7)
• Ans is 128
  
  This is a problem of Selection not Combination.
  
  4P1 * 4P1 * (4P1+4P1) // using +(OR) for selecting any1 of the last 2groups
  =4*4*(8)= 128
• 10 years agoHelpfull: Yes(5) No(10)
• 4*4*4+4*4*4+4*4*4+4*4*4 = 256
• 10 years agoHelpfull: Yes(5) No(0)
• there are 3 places to fill
  and we have 4 grp
  so
  4*3*2=24
• 7 years agoHelpfull: Yes(1) No(2)
• ans is 256
• 10 years agoHelpfull: Yes(0) No(0)
• can u plz xplain hw its 256
• 10 years agoHelpfull: Yes(0) No(0)
• gulsan gave perfect soltn thnx
  
• 10 years agoHelpfull: Yes(0) No(0)
• gulsan gave perfect soltn thnx
  
• 10 years agoHelpfull: Yes(0) No(1)
• gulsan gave perfect soltn thnx
  
• 10 years agoHelpfull: Yes(0) No(1)
• ans is 256
• 7 years agoHelpfull: Yes(0) No(1)