In a class every one will play atleast one sport viz table tennis,cricket n badminton. 73 students play table tennis, 79 play badminton, 75 play cricket and 25 students play both tt n badminton, 24 play both tt n cricket 30 play badminton n cricket n16 students play all d sports
3)how many students r der in d class
4)how many students play only cricket.

total student in class
n(t U b U c)=n(t) +n(b) +n(c) -n(t U B) -n(t U c) -n(b U c) +n(t I b I c)
=73+75+79-30-24-25+16=164 here U is union and I is intersection
only cricket
n(c)-n(t U c) -n(b U c)+n(t I b I c)=75-24-30+16=37
10 years agoHelpfull: Yes(58) No(12)

1.N(BUTUC)=N(T)+N(B)+N(C)-N(B∩T)-N(B∩C)-N(C∩T)+N(B∩T∩C)
N(BUTUC)=73+79+75-25-30-24+16
N(BUTUC)=164
2.PERSONS PLAY CRICKET ONLY=N(C)-N(B∩C)-N(C∩T)-2(N(B∩T∩C))
=75-30-24-(2*16)
=37
10 years agoHelpfull: Yes(7) No(2)
only cric= 37
total students=164
10 years agoHelpfull: Yes(6) No(0)
only play cricket=75-(24+16+30)=5
only play tennis=73-(24+25+16)=8
only play badminton=79-(25+16+30)=8
total students=8+8+5+24+25+30+16=116
10 years agoHelpfull: Yes(5) No(13)
1)164
2)42
10 years agoHelpfull: Yes(4) No(0)
only Cricket=37
total students=117+14+16+8+9=164
10 years agoHelpfull: Yes(3) No(0)
1. 116
2. 5
10 years agoHelpfull: Yes(1) No(1)
to calculate total number of student that will be
73+79+75-25-24-30+16=164
the number of student play only cricket will be
75-24-30-16=51-30-16
=21-16
=5
10 years agoHelpfull: Yes(1) No(1)
total no. of students
= n(B U T U C)= n(B)+n(T)+n(C)-n(B∩T)-n(B∩C)-n(C∩T)+n(B∩T∩C)
= n(B U T U C)= 73+79+75-25-24-30+16
= n(B U T U C)= 164

students play only cricket =
only n(c) = n(C)- n(T U C) - n(B U C)+ n(T ∩ B ∩ C) = 75-24-30+16 = 37
10 years agoHelpfull: Yes(1) No(0)
@rohit raj

why u have added n(t i bi c)in calculating dose who plays only cricket
10 years agoHelpfull: Yes(0) No(0)
only Cricket=37
total num of students=117
10 years agoHelpfull: Yes(0) No(3)
3)164
4)
37
10 years agoHelpfull: Yes(0) No(1)

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