How many different arrangements can be made by using all the letters of the word "INDEPENDENCE" if
(i)D's come together?
(ii)D's do not come together?

• There are 3N, 4E, 2D, 1I, 1P and 1C in the word independence.
  Total arrangements of word INDEPENDENCE =12!/3!*4!*2! = 1663200
  Solution of D's come together : So take two D's together as one D
  Total arrangements = 11!/3!*4! (Since total words with d taken together is 11 and since there are 3 N's and 4 E's together) = 277200
  Solution of D's don't come together : total arrangements - arrangements of D being together = 1663200-277200 = 1386000
• 6 years agoHelpfull: Yes(0) No(0)