If x = 3 + 1 and y = 3 - 1 , then the value of (x2 + y2) is:

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• is it TCS qn?
  
  x = 3 + 1 =4
  y = 3 - 1 =2
  so (x^2+y^2)=4^2+2^2=20
• 11 years agoHelpfull: Yes(22) No(2)
• 20
  x=(3+1)=4
  y=(3-1)=2
  (X^2+y^2)=(4^2+2^2)=(16+4)=20
• 11 years agoHelpfull: Yes(2) No(0)
• ((3+1)2+(3-1)2)
  (4*2+2*2)
  8+4
  12
• 11 years agoHelpfull: Yes(1) No(1)
• 4^2+2^2=16+4
  =>20
• 11 years agoHelpfull: Yes(1) No(1)
• (4)2+(2)2=12. ans is 12
• 11 years agoHelpfull: Yes(1) No(0)
• x=3+1=4
  y=3-1=2
  x2=16
  y2=4
  x2+y2=20
  
• 11 years agoHelpfull: Yes(1) No(0)
• X2+Y2=3+1+3-1=6
  
• 11 years agoHelpfull: Yes(0) No(14)
• x=4
  y=2
  (x^2+y^2)=(x+y)^2-2xy
  =6^2-16
  36-16=20
• 11 years agoHelpfull: Yes(0) No(0)
• x=3+1=4;
  y=3-1=2;
  x^2+y^2=16+4=20
  
• 11 years agoHelpfull: Yes(0) No(0)
• X=3+1=4
  Y=3-1=2
  X2+y2=X^2+Y^2
  HERE X=4 AND Y=2 SO
  X2+Y2=4^2+2^2=16+4=20
• 11 years agoHelpfull: Yes(0) No(0)
• x=4,y=2
  
  x^2+y^2=4^2+2^2=20
• 11 years agoHelpfull: Yes(0) No(0)
• x2+y2=(x+y)2-2xy
  =(4+2)2-2*4*2
  =36-16
  =20
• 11 years agoHelpfull: Yes(0) No(0)
• x=4,y=2
  x2+y2=16+4
  =20
• 11 years agoHelpfull: Yes(0) No(0)
• (a+b)^2=a^2+b^2+2ab
  (a-b)^2=a^2+b^2-2ab
  x=3+1:x^2=9+1+6
  x=3-1:x^2=9+1-6
  value is 20
  
  
  otherwise x=4,y=2
  4^2+2^2=20
• 11 years agoHelpfull: Yes(0) No(2)