Square A is formed with the diagonal of square B as its sides and square B has the diagonal of square C as its side? Find the ratio of the area of square C to square A?

• -----------correction in previous soln-------
  ans 1:4
  
  let side of square C is = x => area of square C = x^2
  
  diagonal of C = √2* x =side of square B
  
  diagonal of B = √2*(√2* x)= 2x = side of square A
  => area of square A = (2x)^2 = 4*x^2
  
  reqd ratio =(area of square C )/ (area of square A) = x^2 /4*x^2 = 1:4
  
• 10 years agoHelpfull: Yes(37) No(1)
• let side of square C is = x => area of square C = x^2
  
  diagonal of C = √2* x =side of square B
  
  diagonal of B = √2*(√2* x)= 2x = side of square A
  => area of square A = (2x)^2 = 4*x^2
  
  reqd ratio =(area of square C )/ (area of square A) = 4*x^2 / x^2 = 4:1
  
  ans 4:1
  
• 10 years agoHelpfull: Yes(5) No(5)
• 1:4 i think
  
• 10 years agoHelpfull: Yes(0) No(0)
• square C B A
  SIDE a a x sqrt2 2a
  DIAGONAL a x sqrt2 2a 2 x a x sqrt2
  AREA a^2 2a^2 4a^2
• 10 years agoHelpfull: Yes(0) No(0)
• ans is:1:4
  
• 10 years agoHelpfull: Yes(0) No(0)
• let side of square C is = x => area of square C = x^2
  
  diagonal of C = √2* x =side of square B
  
  diagonal of B = √2*(√2* x)= 2x = side of square A
  => area of A = (2x)^2 = 4*x^2
  
  ratio =(area of C )/ (area of A) = 4*x^2 / x^2 = 4:1
  
  ans 4:1
• 9 years agoHelpfull: Yes(0) No(2)