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Maths Puzzle
Numerical Ability
(x-a)(x-b)(x-c)....(x-z)=?
1. x to the power 26 +....+y to the power 26.
2. its a binomial hv to solve
3.xyz
4 1
5 0
Read Solution (Total 3)
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- (x-a)(x-b)(x-c)....(x-z)
there is a factor (x-x)=0
so, (x-a)(x-b)(x-c)....(x-z)=0 - 10 years agoHelpfull: Yes(3) No(2)
- very simple question
in middle term (x-x)=0
when 0 multiply by any number ans become zero
so ans is 0
thank you - 10 years agoHelpfull: Yes(1) No(2)
- zero because in in that series (x-x) comes so entire becomes zero....
- 10 years agoHelpfull: Yes(0) No(0)
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