A bag Contains 1 2 5 Rs coins in ratio 4 8 5 and total amount of 90 Rs how

assume that there are 4x,8x,5x coins of 1,2,5 rs respictively as for the question.
Then (4x*1)+(8x*2)+(5x*5)=90
then x=2
now there has 4,16,10 coins of 1,2,5 Rs respictively
10 years agoHelpfull: Yes(4) No(0)
Its simple!!
we will solve it by using the value of each coin.x be identity ratio
let the ratio be 4x,8x,5x
When we add this to become 90 as it says that the coins 1,2,5 are in ratio 4:8:5
we will multiply every ratio by their face value
4x*1+8x*2+5x*5=90
45x=90
x=2
Therefore the number of coins be Re 1=8,Rs2=32 Rs 5=10
10 years agoHelpfull: Yes(2) No(1)
4x*1+8x*2+5x*5=90(coz given ratio is 4:8:5)
45x=90
x=2
So no. of 5 rupee coin is = 5x = 10
10 years agoHelpfull: Yes(2) No(0)
ans) 10
---> 4x*1 + 8x*2 + 5x*5 = 90
---> 4x + 16x + 25x = 90
---> 45x = 90
---> x = 2
So, the ratio becomes 2*4:2*8:2*5 ==> 8:16:10
so, there are 8 Rs.1 coins, 16 Rs.2 coins and 10 Rs.5 coins...
10 years agoHelpfull: Yes(1) No(0)
Given Ratios is 4:8:5 .

Total 1 Rupee coin is = Rs. 4x*1
Total 2 Rupee coin is = Rs. 8x*2
Total 5 Rupee coin is = Rs. 5x*5

Total amount 4x+16x+25x = 90;
45x=90;
x=2;
no. of 5 rupee coin are = 5x = 10
10 years agoHelpfull: Yes(1) No(0)
4x*1+8x*2+5x*5=90
45x=90
x=2
total no. of 5.rs coins are 5x, so 5x=5*2=10
10 years agoHelpfull: Yes(0) No(0)
5 rs coins are=10
5*10=50
2*16=32
1*8=8
Total 90
8 years agoHelpfull: Yes(0) No(0)

A bag Contains 1,2,5 Rs coins in ratio 4:8:5 and total amount of 90.Rs. how many 5.Rs coins are there in that bag...?