A man reaches his office two hours late travelling at 50 km/hr.if he increases his speed to 60km/hr,he is late by 1 hour. find the distance he has to travel to reach his office and speed required to reach the office in time

• let distance be d km & time reqd be t hour then
  d/50 = (t+2)
  d/60 = (t+1)
  => 50(t+2)=60(t+1)
  => 5t+10=6t+6
  => t=4
  put t=4 in eqn d/50=(t+2)=> d=50(4+2)=300
  
  d = 300 km & t = 4 hour
  
• 10 years agoHelpfull: Yes(84) No(4)
• If x is the distance , then
  x/50- x/60 =1
  x= 300 kms
  Then total time allowed for reaching in time = 300/60 -1 = 4 hrs
  Speed required to reach in time = 300/4 = 75 kms/hr
• 10 years agoHelpfull: Yes(40) No(0)
• assume the distance is x
  the according to our question
  (x/50)-(x/60)=1
  x=300km;
  time to be taken=300/50=4 hrs
• 10 years agoHelpfull: Yes(10) No(8)
• let time =t;
  50*(t+2)= 60*(t+1);
  t=4
• 10 years agoHelpfull: Yes(4) No(0)
• There is formula to find out total distance => ( v * u )( p + q )/( v - u )
  where : 'p' hours late travelling at a speed of 'u' kmph
  &'q' hours early travelling at a speed of 'v' kmph
  
  Here 'q' also late. So we take as a negative value for 'q'
  
  So p = 2hrs at speed u = 50kmph
  & q = -1hrs at speed v = 60kmph
  
  So total distance = ( 60 * 50 )( 2 - 1 )/( 60 - 50 ) = 300km
  So actual time = 300/60-1 =4hrs
  
  So required speed = 300/4 = 75kmph
• 10 years agoHelpfull: Yes(2) No(4)
• distance=300 km
  time=4hour
• 10 years agoHelpfull: Yes(1) No(2)
• distance is 300 km
  time is 4 hrs
• 10 years agoHelpfull: Yes(1) No(2)
• let distance be d km & time reqd be t hour then
  d/50 = (t+2)
  d/60 = (t+1)
  => 50(t+2)=60(t+1)
  => 5t+10=6t+6
  => t=4
  put t=4 in eqn d/50=(t+2)=> d=50(4+2)=300
  
  d = 300 km & t = 4 hour
• 8 years agoHelpfull: Yes(1) No(0)
• Dipin , thanx for your solution
  the most perfect ans with less time
• 9 years agoHelpfull: Yes(0) No(0)
• suppose distance of his office is x and time =t
  when speed is 50km/hr then by formula speed =distance/time
  
  50=x/(t+2) as he reaches 2 hr late by actual time
  
  x=50*(t+2) this is equation 1
  
  same as for 60km/hr speed
  x=60*(t+1) this is equation 2
  
  
  by comparing 1 and 2
  we get t=4
  now put t in any equation
  we get x= 300km
  now speed to reach office in time= 300/4= 75km/hr
  
• 8 years agoHelpfull: Yes(0) No(0)
• speed * time = > 50* 2 * 5/18 = (x+18)* 5/18 *1
  500/18 = 5/18 + 300/18
  200/18 = 5/18
  5 x = 200
  x = 40
• 8 years agoHelpfull: Yes(0) No(0)