Q. The no of ways in which 8 person can be seated at a round table if 2 particular persons must always sit together
Option
a) 288
b) 720
c) 1440
d) 2880

• 8 persons can be seated in 7! ways
  But, when 2 persons are sitting together they will be considered as a single unit and number of ways of their arrangement will be 6!
  and their independent arrangement will also be taken into account
  
  Hence,
  
  the no. of ways are 2*6!=1440
  answer=1440
• 10 years agoHelpfull: Yes(38) No(6)
• (n-1)! is the number of ways n people can be made to sit at a round table. Here 2 people need to sit together. So, we consider these two people to be a unit and the ways they can be arranged together with the group becomes 6!. Now, the two people considered as a unit can be arranged among themselves in 2! ways. Hence, 6!*2!=1440 is the required answer.
• 10 years agoHelpfull: Yes(18) No(0)
• 8 persons can be seated at a round table in (8-1)! ways..
  2 particular persons sit together, consider them as one unit, so total members will become 7 persons...
  7 persons sit around a table in (7-1)! ways = 6! = 720
• 10 years agoHelpfull: Yes(6) No(19)
• =(7-1)!*2
  =6!*2
  =1440
  
• 10 years agoHelpfull: Yes(4) No(2)
• Lets apply here a rope method.
  formula for circular arrangement: if "n" to be sit in a circular fashion then total number of ways is (n-1)!
  and here 2 people should always sit together so lets tie them with a rope and consider them as a one person for a while. so total person will be 7, n=7
  so (n-1)! -> (7-1)!= 6!= 720 and the two people can arrange them self in 2! way so total number of ways will be 720 * 2!= 1440
• 10 years agoHelpfull: Yes(4) No(0)
• 1440
  6 people sits in 6 seats in 6! way and in every case the remaining 2 people can be in two ways , so the no of ways will be 6!*2= 1440
• 10 years agoHelpfull: Yes(2) No(0)
• 6!*2 = 1440 ;six person arrangement multiply by two person arrangement
• 10 years agoHelpfull: Yes(2) No(1)
• c)1440
  6*5*4*3*2*2=1440
  
• 10 years agoHelpfull: Yes(1) No(1)
• there are 8 persons
  so ,in a circular combination (n-1)!
  but two are always together so 7!
  now 6!*internal combination ie 2!
  6!*2!=1440
• 10 years agoHelpfull: Yes(1) No(0)
• take two man as one.now 7 men can sit in 6! for circular arrangement.
  and two man can exchange there sit in 2 ways.so no of ways =2*6!=1440
• 9 years agoHelpfull: Yes(1) No(0)
• b)720 is the answer
• 10 years agoHelpfull: Yes(0) No(3)
• 7 set
  now 6!*2!=1440
  
• 10 years agoHelpfull: Yes(0) No(0)
• total no of ways : (2+6P6) *2
• 10 years agoHelpfull: Yes(0) No(0)
• 720
  8pesons ,2 particular people sit together
  7!
  it is a round so (7-1)!
• 10 years agoHelpfull: Yes(0) No(1)
• 1440
  6 people sits in 6 seats in 6! way and in every case the remaining 2 people can be in two ways , so the no of ways will be 6!*2= 1440
  
• 10 years agoHelpfull: Yes(0) No(0)
• C asdasddd
• 4 years agoHelpfull: Yes(0) No(0)