Q. What is the missing number of the following sequence
9, 35, 91, 189, _, 559

• ans 341
  
  1^3+2^3=9
  2^3+3^3=35
  3^3+4^4=91
  4^3+5^3=189
  5^3+6^3= 341 ------ ans
  6^3+7^3=559
  
• 10 years agoHelpfull: Yes(2) No(0)
• 9=2^3+1^3
  35=3^3+2^3
  91=4^3+3^3
  189=5^3+4^3
  341=6^3+5^3
  559=7^3+6^3
  
  so 341 is answer.
  Here ^3 means power to 3 or cube of the number.
• 10 years agoHelpfull: Yes(0) No(0)
• 2^3+1^3=9
  3^3+2^3=35
  4^3+3^3=91
  5^3+4^3=189
  6^3+5^3=441
  7^3+6^3=559
• 10 years agoHelpfull: Yes(0) No(0)
• First term=9=1+8=1^3+2^3,2nd term=2^3+3^3=35 so,for nth term=(n)^3+(n+1)^3.so in this n=5,so 5th term=5^3+(5+1)^3=341.
• 10 years agoHelpfull: Yes(0) No(0)