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Q. A race track is in the form of a ring whose inner circumference is 352 m. and the outercircumference is 396 m. What will be the width of the track?
Read Solution (Total 3)
-
- let outer radius be R & inner radius be r
then,
2*pi*R=396 => R = 396/2 *7/22 = 63
2*pi*r=352 => r = 352/2 *7/22 = 56
so, width of the track =(R-r)meters =(63-56)m = 7 m - 10 years agoHelpfull: Yes(2) No(0)
- 7 metre...
2*pi*r1=352
r1=56.022
2*pi*r2=396
r2=63.025
r2-r1=7.0028 ans... - 10 years agoHelpfull: Yes(1) No(1)
- 2*(22/7)*(R-r)=396-352
(R-r)=44*7/(22*2)=7 - 10 years agoHelpfull: Yes(0) No(0)
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