milkha singh and tomar was running for a marathon....frm ramnagar to jamnagar...there are two cities between ramnagar and jamnagar ramgarh and rampur and distance between these two cities are 15 km..if milkha singh ran ramnagar to ramgarh in 90 mnts with speed 40km/hr and Vkm/hr(v is whole number) speed from ramgarh to rampur in 30 mnts....As tomar is professanalist so he maintain constain speed during the marathon....and they both reached at n hour find out the value of n..
1.5
2.15
3.41
4.all of above

• Please Completely state the question
• 10 years agoHelpfull: Yes(5) No(0)
• it is not complete...
  
  tomar's const speed is 18 km/h....
  
  
  
  Solution:-
  rn-----rg---rp-----jn
  
  let d1,d2,d3 be respective distances...
  so d1=40*(3/2)=60km
  d2=15 km
  
  
  given const speed of tomar=18km/h
  so 18=(75+d3)/n
  so d3=18n-75 ------(1)
  
  now coming over to milkha
  let speed of milkha over d3 is v
  so,
  v=d3/(n-(3/2+1/2))=d3/(n-2) //*time is given for d1 & d2 of milkha*//
  from (1)
  v=(18n-75)/(n-2)
  
  
  
  As long as n>75/18 everything is fine.....hence all of above..:)
• 10 years agoHelpfull: Yes(3) No(0)
• Answer is 5 hrs......
• 8 years agoHelpfull: Yes(1) No(0)
• Answer is 41
  @Atul not for every value of n>75/18 v will be a whole number
• 9 years agoHelpfull: Yes(0) No(0)
• ans 1 dont consider jamnagar
  mika=reached rampur by 2 hours=90min+30min=120 min=2 hour+jamnag time
  tomar=75/18=25/6= 4 1/6
  reach time =1st one time +2nd one time=5 hour 10 min
• 9 years agoHelpfull: Yes(0) No(0)
• Can anyone expln it clrly..
• 9 years agoHelpfull: Yes(0) No(0)