Two trains leaving from two station 50 miles away from each other with costant speed of 60 miles per hour, approaches towards each other on diffrent tracks. if lenght of each train is 1/6 mile. when they meet How much time they need to pass each other totally?

• both are approaching each other relative speed=60+60=120m/h
  distance=50m
  time=50/120=5/12hrs= 25 minutes to meet
  
  now,
  relative length of train= 1/6+1/6=1/3m
  relative speed = 120m/h
  time to cross both the trains= (1/3)/120=1/360 hrs
  = 1/6 minutes ans...
• 10 years agoHelpfull: Yes(26) No(2)
• The trains are coming towards each other so their relative speed is 60+60=120
  In this case the distance would be addition of lengths of trains.i.e 1/6+1/6=1/3
  s=d/t, t=d/s=1/3*120=1/360hours.
• 10 years agoHelpfull: Yes(11) No(2)
• a...............................b
  A(speed) 60 mile/h 50 miles B(speed) 60 mile/h
  length of A = 1/6 mile length of B = 1/6 mile
  total distance = 50 + 1/6 + 1/6 = 151/3 mile
  time = 151/3
  ........... = 151/360h
  120
• 10 years agoHelpfull: Yes(6) No(4)
• relative speed=(60+60)=120 miles/hr
  each train has to cover(own length+another train's length)=(1/6+1/6)mil=1/3 mile
  time taken=(1/3*120)hrs=1/360 hrs=10 seconds
• 10 years agoHelpfull: Yes(4) No(3)
• u+v=60*1.603km*2,
  t=distance/speed,
  t=(2*1/6*1.603)/(60*1.603*2)=(1/360)hr=(1/6)min.
• 10 years agoHelpfull: Yes(2) No(1)
• they will meet at 25 miles found by considering at an instant both will be at apoint so time is same if one travels x distance other travels 50-x so using d/v=constant distance is found...as both are in opposite direction their speeds get added up as 120 miles/hr and length of train is 1/6 mile so time they travel together is distance/time=1/6/120=5 sec
• 10 years agoHelpfull: Yes(0) No(1)
• 
  initially : a 1/6
  |----------> b 1/6
  
  
• 10 years agoHelpfull: Yes(0) No(1)