There are three departments having students 64,58,24 .In an exam they have to be seated in rooms such that each room has equal number of students and each room has students of one type only (No mixing of departments). Find the minimum number of rooms required?

• WE NEED TO TAKE GCD WHICH IS 2
  THUS ALL THE ROOMS WILL HAVE 2 STUDENTS OF THE SAME DEPT
  1) 64/2 = 32
  2) 58/2 = 29
  3) 24/2 = 12
  
  TOTAL NO. OF MIN ROOMS REQD = 32+12+29 = 73 ......ANS
• 13 years agoHelpfull: Yes(43) No(1)
• 73 rooms required.
  Each room will have 2 students.
  So totally 73 rooms needed to accommodate 146 students with specified condition satisfied.
• 13 years agoHelpfull: Yes(4) No(4)
• its 2 definately
  find HCF of these numbers
• 13 years agoHelpfull: Yes(3) No(4)
• y cant we accommodate 64 stu in 2 classes...i.e.,32*2 ...likewise other two depts.....so total minimum rooms wil b 6 r8?? ANS:6??
• 10 years agoHelpfull: Yes(1) No(5)
• each room having equal no of students required so 8students present in one room
  64/8=8
  24/8=3
  58/8=7
  balance 2 students present in one class
  so 8+3+7+1=19
• 9 years agoHelpfull: Yes(0) No(10)