Out of forty students, there are 14 who are taking Physics and 29 who are taking Calculus. What is the probability that a randomly chosen student from this group is taking only the Calculus class?

• Out of forty students, there are 14 who are taking Physics and 29 who are taking Calculus.
  it means 3 students are taking both subjects.
  29-3=26 are taking calculus only.
  probability that a randomly chosen student from this group is taking only the Calculus class = 26/40 = 13/20
  
• 13 years agoHelpfull: Yes(54) No(2)
• 29 students take Calculus.
  40 - 29 = 11 do not take Calculus.
  14 take Physics.
  14-11(take only Physics) = 3 take both.
  29-3 = 26 take only calculus.
  Thus, Probability of only Calculus student = 26/40 = 13/20
• 13 years agoHelpfull: Yes(12) No(0)
• STUDENTS TAKING
  ONLY PHYSICS = 11
  ONLY CALCULUS = 26
  BOTH = 3
  
  PROB(ONLY CAL) = 26/40 = 13/20 = 0.65 = 65%
• 13 years agoHelpfull: Yes(8) No(2)
• (F+x1+x2+x3+x4+x5+W)/6=A
  after 10 years
  (c+x1+10+x2+10+x3+10+x4+10+x5+10+W+10)/6=A
  take C=0 for child ..solve the upper 2 equations..
  i.e F=50 for present age of father=F+10=60
• 13 years agoHelpfull: Yes(2) No(8)
• ans=26/40
  sol:total there are 40 students (t)
  so p intersection c is =(p+c)-t
  =(14+29)-40 = 3
  so students only studying calculus are 29-3=26
  so probability = 26/40
• 9 years agoHelpfull: Yes(2) No(0)