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Maths Puzzle
Numerical Ability
Permutation and Combination
Prove that...
0!=1....
Read Solution (Total 2)
-
- n! = n(n-1)!
If we let n = 1, we can find 0!:
1! = 1(0!)
0! = 1 - 10 years agoHelpfull: Yes(4) No(2)
- nPr = n!/(n-r)!
when r = 0
0! = nPo (n P zero) = n!/(n-0)!
0! = n!/n!
so
0! = 1 proved - 10 years agoHelpfull: Yes(3) No(1)
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