C does half as much in a day as A and B can do together, and B does half as much again as A. If all there working together can mow 20 hectares of barely in 16 days, how long would each , working by himself take to mow 5 hectares?

• 1/a+1/b=2/c
  1/b=1/2a
  &16(1/a+1/b+1/c)=1...........(1 work for mow 20 hect)
  after solving
  c=48 days for 20 hect mow
  so for 5 hect c=12 days
  again after solving
  a=9 days & b=18 days
• 10 years agoHelpfull: Yes(11) No(0)
• c can mow 5 hectares in 12 days....b takes 18 days..a takes 9 days
• 10 years agoHelpfull: Yes(5) No(9)
• 1/A+1/B=1/2C.......(i)
  1/B=1/2A
  1/A+1/B+1/C=1/16
  FROM (i)
  1/2C+1/C=1/16
  3/2C=16
  C=24
  BUT IT HAS TO MOW ONLY 5 HECTARES
  24/4=6 DAYS
  AGAIN PUTTING VALUES OF C WE GET VALUES OF
  A=9 DAYS
  B=18 DAYS
  
  
  
• 10 years agoHelpfull: Yes(5) No(7)
• c will mow 5 hectares in 13 days, b in 26/3 days and c in 52/3 days
• 10 years agoHelpfull: Yes(1) No(5)
• Let 1 day work of A=1/x
  then B-1day work- 1/2x \\ 1/2 of A
  A+B=1/x+1/2x= 3/2x
  C-1day work- 3/4x \\ 1/2 of A+B
  A+B+C= 1/x + 1/2x + 3/4x= 9/2x\\ A,B&C's together work in 1 day.
  In 16days they together mow 20hectares
  In 1 day they together mow 20/16= 5/4 hectare
  So, 9/2x=5/4 => x=3.6 day
  2x= 7.2 day, 4/3x=4.8 day
  Hence it will take 3.6, 7.2 and 4.8 day respectively by A,B&C to mow 5 hectares each.
• 10 years agoHelpfull: Yes(1) No(5)
• 15A/4 * 5*16divide by A*20=15 days
• 10 years agoHelpfull: Yes(1) No(1)
• COULD U PLS ELABORATE HOW??/
• 10 years agoHelpfull: Yes(0) No(3)
• mow 5 hectares by A,B,C in 9,8,12 respectively.
• 7 years agoHelpfull: Yes(0) No(2)
• C = (A+B)/2
  B=A/2
  So,
  Efficiency of A:B:C=4:2:3
  Now total efficiency=4+2+3=9
  Total work=9*16=144
  and 144 value is =20 hectares
  Now,
  5 hectares=(144/20)*5=36
  Then A takes time=36/4=9
  B=36/2=18
  C=36/3=12
• 2 years agoHelpfull: Yes(0) No(0)