Food is sufficient for 100men for 60days. For how many days the food
is sufficient for 500men?

• here use this formula man*time/work
  (man1*time1)/work=(man2*time2)/work
  put here value
  (100*60)/work=(500*time)/work
  by solving this equation u will get days(time)=12
• 13 years agoHelpfull: Yes(23) No(5)
• food z sufficient for 100 men = 60 dayz
  food z sufficient for 1 men= 60*100 dayz
  .....................500 men=60*100/500 =12 dayz
• 13 years agoHelpfull: Yes(13) No(0)
• by using m1d1=m2d2
  where m is men and d is days
  hence m1=100 d1=60 and m2=500 and d2=x
  100*60=500*x
  where x is 12
• 13 years agoHelpfull: Yes(10) No(0)
• 500*x=100*60
  therefore x=12
• 13 years agoHelpfull: Yes(6) No(0)
• for 12 days.
• 13 years agoHelpfull: Yes(4) No(1)
• (60*100)/500=12 days
• 13 years agoHelpfull: Yes(1) No(0)
• man*day=constant
  therefore 100*60=500*x
  x=12
• 13 years agoHelpfull: Yes(1) No(0)
• here use this formula man*time/work
  (man1*time1)/work=(man2*time2)/work
  put here value
  (100*60)/work=(500*time)/work
  by solving this equation u will get days(time)=12
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• food is sufficient for 100 men = 60 days
  food is sufficient for 500 men = x days
  so according to first statement 100 * 60 = 6000
  so for 500 men = 6000/500 = 12 days
• 9 years agoHelpfull: Yes(0) No(0)
• for one man food last for 100*60 days
  so for 500 men food last for (100*60)/500= 12 days.
• 9 years agoHelpfull: Yes(0) No(0)