A tap can fill a tank in 48 minutes another tap can empty it in 2 hours. if both the taps are opened at 11.40 am. then at what time will the tank be filled?

• 1:00 pm
  1 min. filling =1/48
  1 min. empty=1/(2*60)
  In 1 min. tank will be filled (1/48)-[1/(2*60)]=1/80
  So tank will completely filled in 80 min. from the start
  So 11:40+ 80 min=1:00 PM
  
• 10 years agoHelpfull: Yes(3) No(0)
• 1 baje bhar jayegi tanki..
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• the tank at the time 12:11
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• The ans is 1.00PM
  1) first make two given values are same in format(units)...
  (48mins & 120mins)
  2) take a lcm of two numbers is 240
  3) now we can find a 1min value
  4) in 1 min the tap fill the tank 5 lit...(240/48)
  5) in 1 min the another tap empty the tank 2 lit...(240/120)
  6) so the net value of the tank filled by 1min is 3lit...
  7) so finally the tank filled after 80 mins (1hr 20mins)
  8) if both taps are opened at 11.40 so the tank to be filled after 1.00PM
• 10 years agoHelpfull: Yes(0) No(0)