the price of sugar having gone down by 10%,Sharad can buy 6.2kg more for Rs. 279.The difference between the original and the reduced price(per kg) is?

• If initial price is Rs. x and final price is 0.9x, then
  (279/0.9x -(279/x)=6.2
  (310-279)/x=6.2
  x= 31/6.2= Rs 5
  Diff between the original and the reduced price(per kg)= 5*0.1= Rs 0.5 = 50 paise
• 10 years agoHelpfull: Yes(3) No(1)
• rduce price is =279/6.2 = 45 rs
  original price is 50rs different is 50-45=5
  
• 10 years agoHelpfull: Yes(1) No(7)
• let total amount of sugar be x kg...so original price is 279/x per kg....n now it is 279/(x+6.2) per kg....now price has decreased by 10%...so 279/x-10%of279/x=279/(x+6.2)...we get x=55.8 kg...so difference is 5-4.5=.5rs..
• 10 years agoHelpfull: Yes(1) No(1)
• reduced price = 10%of 279=27.9
  6.2kg more buy so 27.9/6.2=4.5
  new rate =4.5
  old rate=new*100/100-10
  4.5*100/90=50
• 9 years agoHelpfull: Yes(0) No(1)