How many 5 no. digit no. can be formed with digits 1,2,3,4,5,6 which are divisible by 4 and digits not repeated
Option
a) 144
b) 168
c) 192
d) none

• last 2 digits can be 12,16,24,32,36,52,56,64.
  so total possible 5 digit numbers = 8*4*3*2= 192 numbers
• 10 years agoHelpfull: Yes(14) No(6)
• 8*4*3*2 means the last 2 digits numbers (12,16,24,32,36,52,56,64)are 8, and 4 remaining numbers choose probability 3 numbers.....4p3...
  answer is 192....
  
• 10 years agoHelpfull: Yes(4) No(1)
• The last 2 digits should be divisible by 4 for the number to be divisible by 4.So, the last 2 digits will be 12,16,24,56,52,32,36,64.The remaining three vacant places can be replaced by any of the 3 digits out of 4.
  So,total Possible 5 digit numbers out of this = 8 * 4p3= 192.
• 10 years agoHelpfull: Yes(3) No(0)
• plz clear me 8*4*3*2
  wt logic is this?
  
• 10 years agoHelpfull: Yes(0) No(0)
• as the question given that 1 2 3 4 5 6 can be divisible by 4
  so if we check 5 no then
  12346 = 144 which is divisible by 4
  and also digits cant repeated so only 5 digit is remaining
  so ans is 144
• 10 years agoHelpfull: Yes(0) No(2)
• acrding to me frst 120 no made by 12 then 2nd 120 made by 16 and so on .. so ans is 120 * 8 = 960 ...
• 10 years agoHelpfull: Yes(0) No(2)
• sorry 192 is crct ans
• 10 years agoHelpfull: Yes(0) No(0)
• pls clear what that logic u using 8*4*3*2=192 pls tell brief expalnati
• 10 years agoHelpfull: Yes(0) No(0)
• pls clear what that logic u using 8*4*3*2=192 pls tell brief expalnati
• 10 years agoHelpfull: Yes(0) No(0)
• plz clear me 8*4*3*2
  wt logic is this?
• 10 years agoHelpfull: Yes(0) No(1)
• 192 perfect.
  The number which are divisible by 4 is can be find by looking last two digit.
  so the combination are(12,16,24,32,36,52,56,64)=total 8 combination for last two digits.
  now 3 digit are left and 4 option also.
  i.e for first three digit(4*3*2*8)=192.
• 7 years agoHelpfull: Yes(0) No(0)