find the probability of 53 sundays in a leap year

• In a Leap Year, there are 366 Days.
  366 Days = 52 Weeks and 2 Days
  Thus, a Leap Year has always 52 Sundays.
  The Remaining 2 Days can be :
  (i) Sunday & Monday ; (ii) Mon & Tue ; (iii) Tue & Wed ; (iv) Wed & Thu ; (v) Thu & Fri ; (vi) Fri & Sat ; (vii) Sat & Sun.
  Clearly there are 7 Elementary events associated.
  Let A be the event that a Leap Year has 53 Sundays.
  Clearly, the event A will happen if the last two days of the leap year are either Sun & Mon or Sat & Sun.
  Favourable Outcomes = 2
  Required Probability = 2/7.
• 10 years agoHelpfull: Yes(30) No(0)
• prob of 53 sundays in leap year = 2/7
  53 sundays will appear in leap year if 1st jan is Sat or sunday only.
• 10 years agoHelpfull: Yes(4) No(0)
• 2/7 ans...
• 10 years agoHelpfull: Yes(1) No(0)
• in leap year 52 week and 2 days extra so they may be (mon,tues tues,wed.....)
  
  so ans.2/7
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• In a leap year there are 52 weeks ,each will occur 52 times hense probability of 53 sunday on leap year is 0
• 10 years agoHelpfull: Yes(0) No(8)
• Pls anyone tell me new pattern Of TCS ..And if anyone has Latest TCS paper Please send me on my mail id nehasingh1111990@gmail.com
  
  Thanks :)
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• sun mon tue wed thu fri sat
  mon tue wed thu fri sat sun
  ans 2/7
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• probablity will be 2/7
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• 2/7 is the correct answer.
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