It takes 52 days to complete an agreement deal by a certain number of men.After 17 days,300 men are added and 21 days are reduced.how many men were working initially?

• 52x=17x+(x+300)14
  x=200
• 10 years agoHelpfull: Yes(36) No(3)
• let no. of people initially is x.
  x men takes 52 days to complete the task.
  one days work of x men = 1/52
  17 days work of x men = 17/52
  remaining work = 35/52
  this remaining work (x+300) men can do in 52-17-21 = 14 days.
  now by applying the basic formula
  (m1*d1)/w1=(m2*d2)/w2
  x*52 = {(x+300)*14}/(35/52) because w1 = 1; d1 = 52; w2 = 35/52; d2 = 14
  x = 200.
• 10 years agoHelpfull: Yes(10) No(4)
• Let x no people works initially.
  
  So the left work after 17 days can be done by x people is in 35, but the same work can be done by x+300 is in 35-21=14 days.
  
  so, 35*(x/(x+300))=14
  
  x=200.
  
  initially 200 people worked
• 10 years agoHelpfull: Yes(7) No(10)
• in 17 day total work done is 17/52;
  so remaining work is=35/52
  let initial pepole are x.
  so x pepole can 35/52 work in 35 days
  so x+300 can '''''''''''''''' 35*X/(x+300)=21
  on solving x=200;
• 10 years agoHelpfull: Yes(7) No(3)
• let suppose x men are working
  x men do tha work in(52-17)=35days
  bt
  x+300 do it in 14 day
  so
  35x=(x+300)14
  x=200.
• 8 years agoHelpfull: Yes(7) No(1)
• we Know, if m1 persons can do a work in d1 days and m2 persons can do a work in d2 days,
  then m1*d1=m2*d2
  
  17*m=(300+m)*14
  17m = 4200+14m
  17m-14m = 4200
  3m=4200
  m=1400
• 10 years agoHelpfull: Yes(1) No(15)
• 52x=17x+(x+300)/14 by solving this we get x=200
• 8 years agoHelpfull: Yes(1) No(0)
• 52x=17x+(x+300)1
  x=200
• 6 years agoHelpfull: Yes(1) No(0)
• original number of men be N
  for 52 days it become 52 * N
  after 17 days 300 added so,
  52 - 17 = 35
  after 21 days it reduce so,
  35 - 21 = 14 days
  so, N + 300 work for 17 days
  N men work for 17 days i.e N * 17
  for 1 days it is
  14(N + 300) man days
  => 52N = 17N + 14(N + 300)
  52N = 31N + 4200
  => N = 4200 / 21
  N = 200 man.... answer
• 2 years agoHelpfull: Yes(0) No(0)