X=W^2+1 such that 121 < X < 1331 (11^3=1331).what cannot be the remainder when X is divided by 11 provided X is not a prime number
Option 2/4/6/8

• X=W^2+1 & 11^2 < x < 11^3
  
  its easy to check from options
  if w=12, x=145, x/11 => rem=2
  if w=13, x=170, x/11 => rem=4
  if w=14, x=197(prime)
  if w=15, x=226, x/11 => rem=6
  
  thus we see x/11 gives remainder 2,4,6
  
  ans: 8 can't be remainder.
• 10 years agoHelpfull: Yes(35) No(4)
• @rakesh
  if w =13 x= 170/4, x/11 => reminder is 5
  ...
  if w =16 x= 257/11 ,x/11 =>rem = 4
• 10 years agoHelpfull: Yes(5) No(0)
• ans = 8 cant be the remainder
• 10 years agoHelpfull: Yes(1) No(2)
• @RAKESH, i think your answer is wrong because
  170/11 remainder=5
  
• 8 years agoHelpfull: Yes(1) No(0)
• 4 will be the answer
• 10 years agoHelpfull: Yes(0) No(4)
• X=W^2+1 & 11^2 < x < 11^3
  
  its easy to check from options
  if w=12, x=145, x/11 => rem=2
  if w=15, x=226, x/11 => rem=6
  if w=29, x=730, x/11 => rem 4
  
  thus we see x/11 gives remainder 2,4,6
  
  ans: 8 can't be remainder.
  
• 10 years agoHelpfull: Yes(0) No(2)