Elitmus
Exam
Numerical Ability
Number System
X=W^2+1 such that 121 < X < 1331 (11^3=1331).what cannot be the remainder when X is divided by 11 provided X is not a prime number
Option 2/4/6/8
Read Solution (Total 6)
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- X=W^2+1 & 11^2 < x < 11^3
its easy to check from options
if w=12, x=145, x/11 => rem=2
if w=13, x=170, x/11 => rem=4
if w=14, x=197(prime)
if w=15, x=226, x/11 => rem=6
thus we see x/11 gives remainder 2,4,6
ans: 8 can't be remainder. - 10 years agoHelpfull: Yes(35) No(4)
- @rakesh
if w =13 x= 170/4, x/11 => reminder is 5
...
if w =16 x= 257/11 ,x/11 =>rem = 4 - 10 years agoHelpfull: Yes(5) No(0)
- ans = 8 cant be the remainder
- 10 years agoHelpfull: Yes(1) No(2)
- @RAKESH, i think your answer is wrong because
170/11 remainder=5
- 9 years agoHelpfull: Yes(1) No(0)
- 4 will be the answer
- 10 years agoHelpfull: Yes(0) No(4)
- X=W^2+1 & 11^2 < x < 11^3
its easy to check from options
if w=12, x=145, x/11 => rem=2
if w=15, x=226, x/11 => rem=6
if w=29, x=730, x/11 => rem 4
thus we see x/11 gives remainder 2,4,6
ans: 8 can't be remainder.
- 10 years agoHelpfull: Yes(0) No(2)
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