A cow is tied to the rope of 19mts length what is the increase in the area that the cow

pi(R*R)-pi(r*r)=pi(30*30)-pi(19*19)=1694 sqr mtr.
10 years agoHelpfull: Yes(10) No(0)
initially radius was 19m, so area will be 19*19*pi
now the radius is 30m, so area will be 30*30*pi.
so the change in area will be (30*30*pi)-(19*19*pi)=539*pi
10 years agoHelpfull: Yes(5) No(0)
pi(30*30)-pi(19*19=pi(900-361)=pi*539=1693.32 sq. mts
10 years agoHelpfull: Yes(2) No(0)
first area=3.14*19*19=1153.54 mts2
after increment in length of rope,area=3.14*30*30=2826 mts2
so increase in area=2826-1153.54=1672.46mts2
10 years agoHelpfull: Yes(2) No(0)
whatever be the rope length,the cow moves freely if the other end of the rope is not tied to any immovable objects like trees... so the the area is "infinite" as the cow moves freely
10 years agoHelpfull: Yes(2) No(0)
apply circle concept-piR2-r2put - r30and r 19 ans- 1694m2
10 years agoHelpfull: Yes(0) No(0)

A cow is tied to the rope of 19mts length. what is the increase in the area that the cow can move when the length of the rope is increase from 19 to 30