28a+30b+31c=365. find a+b+c, if a,b,c are natural nos

• a,b,c are nothing but the no. of months having 28,30,31 days in a year of 365 days respectively.
  a=1,b=4,c=7
  28(1)+30(4)+31(7)=365
  so,a+b+c=12
• 10 years agoHelpfull: Yes(104) No(0)
• 28*1(28days of feb) + 30*4(4 months having 30 days) + 31*7(7 months having 31 days)=365
  a+b+c=1+4+7=12
  Hint from 365 ,28,30, 31 numbers
• 10 years agoHelpfull: Yes(17) No(1)
• not always 12 months frnds..it can b also (28*2)+(30*1)+(31*9)=365
  a=2,b=1,c=9.
  a+b+c=2+1+9= 12
• 10 years agoHelpfull: Yes(1) No(1)
• for this you should know about no of days in every month
• 10 years agoHelpfull: Yes(1) No(0)
• 12 no of months in a year
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• months having 28 days=1
  30days=4
  31 days=7
  1+7+4=12
• 10 years agoHelpfull: Yes(0) No(0)
• 28(1)+30(4)+31(7)=365
  1+4+7=12
• 10 years agoHelpfull: Yes(0) No(0)