If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, What time taken by 15 men and 20 boys in doing the same type of work ?

• If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days,
  60 M +80B = 52M+96 B
  Then 8M =16 B
  1M =2B
  6M= 12 B
  6 men and 8 boys = 20 Boys
  15 men and 20 boys = 50 Boys
  so 20 boys can do a piece of work in 10 days
  and 50 boys can do a piece of work in 10*20/50 = 4 days
  
• 12 years agoHelpfull: Yes(29) No(13)
• 26m + 48b = 1/2
  6m + 8b = 1/10
  so m = 1/100 and b = 1/200
  so, 15m + 10b = 25/100 = 1/4
• 12 years agoHelpfull: Yes(13) No(4)
• 6m+8b=2(3m+4b) can do the work in 10 days
  so 3m+4b can do the work in 20 days
  so (15m+20b)=5(3m+4b) can do the work in 20/5=4 days
• 9 years agoHelpfull: Yes(4) No(0)
• 4 days..
  
  
  
  
• 10 years agoHelpfull: Yes(2) No(2)
• Units of work done is measured in terms of man-days, boy-days etc. you will have to find our the number of man-days and boy-days required to do the job and equate it.
  
  10(6M+ 8B) = 2 (26M + 48B) since the same work is done they will be equal
  
  60M + 80B = 52M + 96B
  
  8M = 16B or M = 2B substitute 2B = M and you will get the total man-days required to do the job and it is
  
  10( 6M + 4M) = 100 man-days
  
  Similarly substitute 20B as 10M to find out the answer
  
  x(15M+10M) = 100M
  
  solving this x = 4 so 15 men and 20 boys will have to work for 4 days to complete the job
• 7 years agoHelpfull: Yes(1) No(0)
• 4 days will be answer
• 9 years agoHelpfull: Yes(0) No(1)