Q. The distance from p to q is 25 km,6 km of which is uphills, 12km downhills and the rest 7km in level ground.The time in which the man would go from p to q and back again,supposing his speed uphill is 2km,downhill 3km and level ground 7/2km per hour, is

• t=(1/3 + 1/4 + 2)+(1/2 +1/6 + 2)=5.25 hours
• 10 years agoHelpfull: Yes(2) No(0)
• 19 hour is answer
• 10 years agoHelpfull: Yes(1) No(0)
• speed during uphill= 2kmph
  distance uphill= 6 km
  time, t1= 3h
  speed downhill= 3kmph
  distance downhill= 12 km
  time, t2= 4h
  speed on level ground= 7/2 kmph
  distance = 7km
  time, t3= 2h
  total time= t1+t2+t3=9h
• 10 years agoHelpfull: Yes(1) No(0)
• 2(6/2+12/3+7/3.5)=18
• 10 years agoHelpfull: Yes(0) No(0)
• what is the write answer??
• 10 years agoHelpfull: Yes(0) No(0)
• time=((6/3)+(12/3)+(7/3.5))*2=18
• 9 years agoHelpfull: Yes(0) No(0)
• t=2(6/2+12/3+7/3.5)=18
• 9 years agoHelpfull: Yes(0) No(0)
• form p to q,6/2+12/3+7/(7/2)=9
  from q to p,7/(7/2)+12/2+6/3=10
  so total=10+9=19hrs
• 7 years agoHelpfull: Yes(0) No(0)
• uphill = 12km
  downhill = 24km
  level = 14 km
  time to and fro = 12/2 + 24/3 + 14/3.5 = 18 hrs
• 4 years agoHelpfull: Yes(0) No(0)