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Numerical Ability
Sequence and Series
4 12 8 26 16 56 32 x..? find x
Read Solution (Total 9)
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- 4 12 8 26 16 56 32
4*2=8 12*2=24+2= 26
8*2=16 26*2=52+4= 56
16*2=32 56*2=112+6=118 - 10 years agoHelpfull: Yes(27) No(1)
- 4 12 8 26 16 56 32 x
(4 12) (8 26) (16 56) (32 x)
4*3.00=12
8*3.25=26
16*3.50=56
32*3.75=120=x
x=120 - 10 years agoHelpfull: Yes(9) No(15)
- 12+12=24+2=26
26+26=52+4=56
56+56=112+6=118 - 10 years agoHelpfull: Yes(1) No(4)
- 4*2=8,8*2=16,16*2=32.
12*2=24+2=26,26*2=52+4=56,56*2=112+8=110 - 10 years agoHelpfull: Yes(1) No(1)
- 120 is answer
- 10 years agoHelpfull: Yes(1) No(0)
- 118....alternating series
- 10 years agoHelpfull: Yes(0) No(2)
- take the alternative series 4,8,16,32 this are all can be represented as
2*2=4
2*4=8
2*8=16
2*16=32
and the remaining numbers 12,26,56, can follow
(6*2)+0=12
(12*2)+2=26
(26*2)+4=56
(56*2)+8=120
so x is replaced with 120.. - 10 years agoHelpfull: Yes(0) No(1)
- 4*2=8
12*2=24+2=26
8*2=16
26*2=52+4=56
16*2=32
56*2=112+6=118 - 10 years agoHelpfull: Yes(0) No(0)
- 118 guys
it is an alternating series
here we go
(12*2)+2=26
(26*2)+4=56
(56*2)+6=118
so we get 118 - 10 years agoHelpfull: Yes(0) No(0)
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