In how many possible ways can write 3240 as a product of 3 positive integers a,b and c.

• 3240=2*2*2*5*3*3*3*3
  so,
  no. of ways=8!/(3!*4!)=420......
• 10 years agoHelpfull: Yes(39) No(119)
• Express 3240 as a factors of prime nos
  
  3240 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 5 = 23 x 34 x 5
  
  so these 3 nos of 2's can be distributed to 3 integres a,b,c in : [3+(3-1)]C (3-1) ways i.e 5C2 = 10 ways
  
  Nos of ways in which 4 nos of 3's can be distributed to 3 integers : [4+(3-1)]C (3-1) ways i.e 6C2 = 15 ways
  
  Nos of ways in which 1 nos of 5 can be distributed to 3 integers : [1+(3-1)]C (3-1) ways i.e 3C2 = 3 ways
  
  So total ways = 10 x 15 x 3 = 450
  
• 8 years agoHelpfull: Yes(34) No(3)
• 3240 = 2^3*3^4*5... now x1+x2+x3 = 3 , so no. of solutions : 5C2.. similarily for 3 and 5, we get solns. as 6C2 and 3C2 respectively.. so ans : 5C2*6C2*3c2 = 450.
• 10 years agoHelpfull: Yes(24) No(21)
• wrong answer 280 is coming by 8!/3!*4!.
  please specify how did u get 420.
• 10 years agoHelpfull: Yes(17) No(7)
• hey help me......say the ans how 8!/3!4!1!=420 but it comes 280 only ...........
  
• 10 years agoHelpfull: Yes(16) No(7)
• first take the L.C.M of 3240
  2*2*2*5*3*3*3*3=280
  
  by using permutation concept,we can express it as: 8!/[(3!)(1!)(4!)]
  =1*2*3*4*5*6*7*8/[(1*2*3)(1)(1*2*3*4)]
  =450
• 8 years agoHelpfull: Yes(11) No(34)
• 3240==23×34×51=a×b×c
  We have to distribute three 2's to a, b, c in 3+3−1C3−1=5C2=10 ways
  We have to distribute four 3's to a, b, c in 3+4−1C3−1=6C2=15 ways
  We have to distribute one 5 to a, b, c in 3 ways.
  Total ways = 10×15×3=450 ways
• 9 years agoHelpfull: Yes(10) No(4)
• 2^3*3^4*5...
  5c2 * 6c2 * 3c2=450
  
  [a+b+c=n
  n+r-1Cr-1 solutions]
• 9 years agoHelpfull: Yes(9) No(1)
• 280
  none of these
  
• 10 years agoHelpfull: Yes(7) No(14)
• guys how 2^3 and 3^4 and 5 is written as 5c2 6c2 3c2 plz explain
• 8 years agoHelpfull: Yes(7) No(1)
• it comes only 280..not 420..
  
• 10 years agoHelpfull: Yes(5) No(1)
• 8*5*9*9=3240
  a=8,b=5,c=9(through l.c.m of 3240)
• 10 years agoHelpfull: Yes(4) No(23)
• this are the options given,a) 450 b)420 c)350 d)320
• 10 years agoHelpfull: Yes(4) No(3)
• 3240= 2*2*2*5*3*3*3*3
  8!/3!4!1!=420
  so ans=420
• 10 years agoHelpfull: Yes(4) No(14)
• The factors are 2^3*3^4*5,for 2^3 we get 5C2, for 3^4 we get 6C2, for 5 we get 5C2 and multiple all we get the answer as 450
• 9 years agoHelpfull: Yes(3) No(7)
• Express 3240 as a factors of prime nos
  
  3240 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 5 = 23 x 34 x 5
  
  so these 3 nos of 2's can be distributed to 3 integres a,b,c in : [3+(3-1)]C (3-1) ways i.e 5C2 = 10 ways
  
  Nos of ways in which 4 nos of 3's can be distributed to 3 integers : [4+(3-1)]C (3-1) ways i.e 6C2 = 15 ways
  
  Nos of ways in which 1 nos of 5 can be distributed to 3 integers : [1+(3-1)]C (3-1) ways i.e 3C2 = 3 ways
  
  So total ways = 10 x 15 x 3 = 450
• 8 years agoHelpfull: Yes(3) No(2)
• The factor 2 can be split among 3 divisors in 10 different ways:
  0,0,3
  0,1,2
  0,2,1
  0,3,0
  1,0,2
  1,1,1
  1,2,0
  2,0,1
  2,1,0
  3,0,0
  
  The factor 3 can be split among 3 divisors in 15 different ways:
  0,0,4
  0,1,3
  0,2,2
  0,3,1
  0,4,0
  1,0,3
  1,1,2
  1,2,1
  1,3,0
  2,0,2
  2,1,1
  2,2,0
  3,0,1
  3,1,0
  4,0,0
  
  The factor 5 can be split among 3 divisors in 3 different ways:
  0,0,1
  0,1,0
  1,0,0
  
  Hence the total number of ways to write it as a product of 3 divisors is 10x15x3=450.
• 5 years agoHelpfull: Yes(3) No(0)
• ans:84
  3240 can be written as:5*2*2*2*3*3*3*3
  
  so we have to fill these numbers in multiples of
  116(i.e. with 1num in 100's place & 1num in 10's place...)this combination is possible in 5 series 116---5
  like this
  125---10
  134---17
  224---20
  233---19
  242---13
  total=84
  
  
  this is in my view..
  please specify if you know the options....
  
  
• 10 years agoHelpfull: Yes(2) No(15)
• ans:450
  (p+2)c2*(q+2)c2*(w+2)c2
• 7 years agoHelpfull: Yes(2) No(1)
• iam asking the possibility not the one way to get 3240.plz check it..once
• 10 years agoHelpfull: Yes(0) No(0)
• how 420 wll come as ans is 280????
  
• 9 years agoHelpfull: Yes(0) No(0)
• divya plz xpalin me y u hv tkn combinatn?
  
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is 280 ..
  2*2*2*3*3*3*3*5=3240.
  8!/(3!*4!*1!)=280
• 9 years agoHelpfull: Yes(0) No(4)
• 3240=2*2*2*5*3*3*3*3
  so,
  no.of ways= 8!/3!*4! =8*7*6*5*4*3*2*1/3*2*4*3*2=280
• 9 years agoHelpfull: Yes(0) No(6)
• answer:
  3240 = 23*34*51 = a*b*c
  
  We have to distribute three 2's to a, b, c in 3+3−1C3−1 = 5C2 = 10 ways
  
  We have to distribute four 3's to a, b, c in 3+4−1C3−1 = 6C2 = 15 ways
  
  We have to distribute one 5 to a, b, c in 3 ways.
  
  Total ways = 10*15*3 = 450 ways
• 6 years agoHelpfull: Yes(0) No(0)
• 2*2*2*5*3*3*3*3
• 5 years agoHelpfull: Yes(0) No(1)