In the sequence 1, 2, 3, 3, 3, 4, 4, 4, 4, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 1, 1, 1, 2, 2, 2, 2, 2, 2, ....., what is the 2926th term?

• its 1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,1,1,1,2,2,2,2,2,2,..
  
  1,2,2,3,3,3,4,4,4,4 = 10 terms (1st series)
  1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4 = 20 terms(2nd series)
  1(3times),2(6times),3(9times),4(12times)= 30 terms(3rd series)
  
  Sum of no. of terms= 10+20+30+...+10*n
  =10(1+2+3+...+n)
  =10*n(n+1)/2 < 2926 => n(n+1)< 585.2 => n less than 24
  
  if n=24,Sum of no. of terms= 10+20+30+...+24*n= 10*24*25/2 = 3000
  
  24th series = [1...(24times),2...(48times),3...(72times),4...(96times)]
  
  i.e there are 96 4's before 3000th term
  
  so, 2926th term =4
  
• 10 years agoHelpfull: Yes(27) No(0)
• its 1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,1,1,1,2,2,2,2,2,2,..
  
  1,2,2,3,3,3,4,4,4,4 = 10 terms (1st series)
  1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4 = 20 terms(2nd series)
  1(3times),2(6times),3(9times),4(12times)= 30 terms(3rd series)
  
  Sum of no. of terms= 10+20+30+...+10*n
  =10(1+2+3+...+n)
  =10*n(n+1)/2 < 2926 => n(n+1)< 585.2 => n
• 10 years agoHelpfull: Yes(2) No(2)
• ans.4
  1,2,2,3,3,3,4,4,4,4=10 terms
  1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4=20 terms
  10+20+30+............
• 10 years agoHelpfull: Yes(1) No(1)
• 1st series is=10
  2nd=20
  3rd=30.....
  n(n+1)/2*10
  assume to take n=23(nearest of 2926th term)
  so,the value=2760.(where n=23)
  remaining is 166(2926-2760)
  after this i cant solve pls send the valuable solution for this question.the ans for this is 1.
• 5 years agoHelpfull: Yes(1) No(1)