A person walks at 4km/hr for a particular duration T1 and 3km/hr for another duration T2 and covers a total distance of 36km. If he walks at 4km/hr for the duration T2 and at 3Km/hr for the duration T1, then he covers only 34km. What willl be the time taken by him to cover the one of the legs?
Option
a) 4hrs
b) 7hrs
c) 10hrs
d) 6hrs

• 4T1 + 3T2 =36...(i)
  3T1 + 4T2 =34...(ii)
  4*(i)-3*(ii),we get
  T1=6hrs and T2=4hrs
  
• 10 years agoHelpfull: Yes(32) No(5)
• Ans is c) 10 hrs
• 10 years agoHelpfull: Yes(6) No(4)
• what is the meaning for -----"What will be the time taken by him to cover the one of the legs"...please explain
• 8 years agoHelpfull: Yes(5) No(1)
• so which value should be considered
• 10 years agoHelpfull: Yes(3) No(0)
• Which should be considered T1 or T2?
• 10 years agoHelpfull: Yes(1) No(0)
• 4T1+3T2=36---------(1)
  3T1+4T2=34--------(2)
  (1)*4--->16T1+12T2=144
  (2)*3------>9T1+12T2=102
  ______________________________
  7T1=42
  _______________________________
  
  T1=6 & T2=4
  ANS:6+4=10hrs.
• 5 years agoHelpfull: Yes(1) No(0)
• it takes 10 hrs
• 10 years agoHelpfull: Yes(0) No(1)
• which ans should be considerd??
  
• 9 years agoHelpfull: Yes(0) No(1)
• T2=4 and T1=6
• 8 years agoHelpfull: Yes(0) No(1)
• 4T1+3T2 = 36--------->(1)
  3T1+4T2 = 34............>(2)
  MULTIPLY EQUATION 1 WITH 3 AND EQUATION 2 WITH 4 AND SOLVE IT
  so you can get T1=6,T2 = 4
• 7 years agoHelpfull: Yes(0) No(1)
• Answer to batao bhai...............value to sabki aa gayi hai
• 6 years agoHelpfull: Yes(0) No(1)
• answer is 10.
• 6 years agoHelpfull: Yes(0) No(1)