A gardener changed the size of his rectangle shaped garden by increasing it's length by 40% & decreasing is's width by 20%.Find area of new garden.

• A1= l*b
  A2= (l*140/100)*(b*80/100)=1.12*lb
  
  so, area of garden is by 1.12 times of old area.
• 10 years agoHelpfull: Yes(34) No(0)
• a+b+ab/100;
  a=40 because length is increases;
  b=-20 width decreases;
  40-20-(20*40)/100=20-8
  12%
  
• 10 years agoHelpfull: Yes(10) No(3)
• Let the original length and breadth of the garden be l and b units respectively
  so,
  area= (l*b)=lb units
  
  on increasing the length by 40% new length= l+(l*40%)=(140*l)/100 units
  
  again on decreasing the width by 20% new width= b-(b*20%)=(80*l)/100 units
  
  new area= (l*140/100)*(b*80/100)=1.12 lb units
  
  hence the area of the garden is 1.12 times the original area
• 10 years agoHelpfull: Yes(7) No(0)
• according to the options available fr this qn ... gardens area increased by 12%
  solution: assume that length is 100cm and width is 50cm then the area of the assumed rectangle is 5000cm. now the length is increased by 40%means new length is 140cm and width decreased by 20% means new width is 40cm then the area of the rectangle is 5600. 600/5000*100=12. answer is 12% increases
• 10 years agoHelpfull: Yes(1) No(2)
• 40-20-(40*20)/100=12
• 9 years agoHelpfull: Yes(1) No(0)
• answer is 112
  area of new garden is 112
  let suppose initial area of garden is 100 then
  is increase by 40% means become 140 and area decrease by 20%
  140-28=112
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1.12 is right answer
• 9 years agoHelpfull: Yes(0) No(0)