If X 2-16 0 What is true

x^2-16>0
it is true only if x>4 then the value x^2-16>0
10 years agoHelpfull: Yes(2) No(1)
X^2-16>0 can be written as x^2-4^2>0

=(x+4)(x-4)>0
=(x+4)>0 ==> x< -4
and
(x-4)>0 ==> x> 4

hence, x > 4 or x < -4
10 years agoHelpfull: Yes(1) No(0)
rakesh u r solutionis ryt but in tcs portal mock exam if we answer like u then it indicates wrong answer...
10 years agoHelpfull: Yes(0) No(0)
put value of x>4
eg:when x=5
25-16=9>0
10 years agoHelpfull: Yes(0) No(0)
X^2-16>0
=(x-4)(x+4)>0
x4
10 years agoHelpfull: Yes(0) No(0)
(x+4)(x-4)>0
their are three range ie [infinite to -4),[-4,4],(4 to infinite]
consider a point within 0 which shows [-4,4] false
consider a point 5 then eq is true so (4 to infinte]
and also point -5 then eq is true so [infinite to -4)
n
10 years agoHelpfull: Yes(0) No(0)
x^2-16>0
=>(x+4)(x-4)>0

if we write (x+4)(x-4)=0 then

so x=4,-4

but as here is x^2-16>0 so there will be a range i.e. x>=4 or x
10 years agoHelpfull: Yes(0) No(0)

If X^2-16>0 What is true?