Roy's is now 7 yrs older than Erik and & 2 yrs older than Iris.If in 2 yrs,Roy will be twice as old as Erik, then in 2 yrs ,what would be Roy's age multiplied by Iris age?

• R=E+7=I+2
  R+2=2(E+2)
  (E+7)+2=2(E+2)
  E=5 SO,R=5+7=12,I=12-2=10
  SO,(R+2)(I+2)=14*12=168
• 10 years agoHelpfull: Yes(14) No(2)
• let the present age of Erik be X yrs.
  Roy's age= (X+7) yrs.
  and iris is two years younger than Roy hence,
  Iris' age= (X+5) yrs.
  
  
  after 2 years
  
  Roy's age= (X+9) yrs.
  Erik's age=(X+2) yrs.
  Iris' age= (X+7) yrs.
  according to the question
  2(X+2) = (X+9)
  X=5
  so Roy's age after 2 yrs= (X+9)=(5+9)=14yrs
  and Iris age= (X+7)= 12yrs
  
  so the multiplication of Roy's and Iris' age will be (14*12)=168
  
  
  
• 10 years agoHelpfull: Yes(6) No(4)
• take roy age will be x
  erik x-7
  iris x-2
  in 2 years
  x+2=2(x-7)+2
  by solving this x=14
  s0 roy=16 iris=14
  16*14=224
• 10 years agoHelpfull: Yes(0) No(4)
• Erik x
  Iris y
  Roy x+7 = y + 2
  
  After 2 years
  Erik x + 2
  Iris y + 2
  Roy x + 9 = y + 4
  2(x+2) = x + 9; therefore x = 5 and y =10
  
  Present age = E =5 R =12 I=10
  After 2 years = E=7 R=14 I=12
  R*I = 14 *12 = 168 = ANS
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• let present age of Roy be 'x' years
  so A/Q, present age of Erik and Iris is (x-7) and(x-2)years respectively
  so after two years,age of Roy,Erik and Iris will be(x+2),(x-5)and x years respectively.
  so A/Q
  (x+2)=2(x-5)
  on solving we get x=12
  so Roy's age multiplied by Iris age two years from now= (x+2)*x
  =(12+2)*12years
  =168years
  
  
  
  THANK you
• 9 years agoHelpfull: Yes(0) No(0)
• let roy's age be x, erik be y and iris be z
  roy is 7 yrs older than erik
  it means x+7=y eqn 1, and also 2 yrs older than iris means x+2=z
  solving these we get y=5-z
  now in 2 yrs roy will be twice as old as erik
  so
  x+2=2y
  put x=y-7 frm above eqn 1
  we get y=5,
  frm this we get x=12 and z = 10
  now roys age multipled by iris age after 2 yrs
  (10+2) * (12+2) =168 ans.
• 9 years agoHelpfull: Yes(0) No(1)