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Numerical Ability
Permutation and Combination
There are 4 boxes coloured red,yellow,green,blue.how many combinations are there for atleast one green box or one red box is selected
Option
A.5
B.9
C.6
D.1
Read Solution (Total 10)
-
- at least one red=(R,Y)(R,G)(R,B) = 3 cominations
at least one green=(G,Y),(G,B) = 2 combinations
total = 3+2 = 5 combinations
A.5 - 10 years agoHelpfull: Yes(45) No(3)
- there will be 5 combination.. because a combination of red and green will be common in both the cases.
- 10 years agoHelpfull: Yes(3) No(1)
- there can be 5 combinations
- 10 years agoHelpfull: Yes(2) No(1)
- 4 boxes r present ..we had 2 choose green or red.
combination is asked..so
4c2 will be ans..4!/2!2!=4*3*2/2*2=6 - 10 years agoHelpfull: Yes(1) No(7)
- 4c1+4c1=6
- 10 years agoHelpfull: Yes(0) No(4)
- 12h-->45*x
y h--> 13*x
y=12*5*xx34
5 - 10 years agoHelpfull: Yes(0) No(2)
- atleast 1 green: 1c1*3c1=3
atleast 1 red:1c1*3c1=3
adding both cases:3+3=6 - 10 years agoHelpfull: Yes(0) No(0)
- How u guys came to know tht only two box are selected ....
Please clarify - 10 years agoHelpfull: Yes(0) No(0)
- atleast 1 green: 1c1*3c1=3
atleast 1 red:1c1*2c1=2
adding both cases:3+2=5 - 10 years agoHelpfull: Yes(0) No(0)
- 3c1+3c1=6 i am nt sure....if wrong tell me the correct answer
- 10 years agoHelpfull: Yes(0) No(0)
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