X Z Y X Y Z Y Z X Find the three digits

m not getting dis soln can u explain..?
10 years agoHelpfull: Yes(17) No(5)
Answer is:x=4,y=9,z=5.
1)X+X is giving Y,which means a no less than 10 which implies that X could be 4 maximum.
2)putting X=4(firstly),so we have sum up Y+Z=X,which means Y and Z can be 9 or 5,8 or 6.
3)taking Z=9 and y=5, we get X=4 and 1 carry.
4)Next,Z+Y=Z,which 9+5+1=15.
5)finally X+X+1=9.
Hence solved.
10 years agoHelpfull: Yes(7) No(1)
How u guys are assigning the numbers to the alphbts.........still im confusing..
10 years agoHelpfull: Yes(5) No(1)
439
+493
-----
932
10 years agoHelpfull: Yes(1) No(7)
xzy
+xyz y+z=x n z+y=z both gives diffrnt value i.e both expression giving
------ carry .hence, i> y+z= 1x(two digit) ii> z+y+1= 1z(two digit)
yzx iii>x+x+1=y
z+y+1=1z => 1z-z=y+1 => y=9......
from eq iii. x+x+1=9 =>x=4......
y+z=1x =>y+z=14 =>z=14-9 =>z=5.......
10 years agoHelpfull: Yes(1) No(2)
plz explain
10 years agoHelpfull: Yes(0) No(3)
2x=y,z+y=y+z=z=x z+2x=x so only possible value 0
x=y=z=0
10 years agoHelpfull: Yes(0) No(1)
pls....give clear explanation ...frds
10 years agoHelpfull: Yes(0) No(1)
x must be 4 because (x+x)
10 years agoHelpfull: Yes(0) No(1)

. X Z Y+X Y Z = Y Z X.
Find the three digits