A leap year it is and what is the probability of getting 53 Sundays ???

• there are 366 days in a leap year.
  366=52*7+2 => (52 weeks + 2 days)
  So, 52 Sundays and 2 days
  
  These 2 days can be,
  (Mon, Tue),(Tue, Wed),(Wed, Thu),(Thu, Fri),(Fri, Sat),(Sat, Sun)&(Sun, Mon)
  total = 7 cases
  for 53 Sundays we should have either (Sat, Sun) or (Sun, Mon)
  2 favourable cases out of 7
  so,probability is = 2/7
• 10 years agoHelpfull: Yes(19) No(1)
• Sol.: A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.
  
  The remaining 2 days may be any of the following :
  
  (i) Sunday and Monday
  
  (ii) Monday and Tuesday
  
  (iii) Tuesday and Wednesday
  
  (iv) Wednesday and Thursday
  
  (v) Thursday and Friday
  
  (vi) Friday and Saturday
  
  (vii) Saturday and Sunday
  
  For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.
  
  n(S) = 7
  
  n(E) = 2
  
  P(E) = n(E) / n(S) = 2 / 7
• 10 years agoHelpfull: Yes(2) No(0)