A & B alone can do a piece of work in 12 and 16 days respectively. They work for 8days alternately and remaining work is done by C in 5 days.
In how many days C alone can do the work.

• Work done by A and B in 8 days alternately or 4 days together = 4*(1/12 +1/16) = 4 *7/48 = 7/12 work.
  Balance 5/12 work is done by C in 5 days.
  C alone can do full work in 5*12/5 = 12 days.
• 12 years agoHelpfull: Yes(0) No(0)
• 12 days...
  
  
  
  
  
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)