The age of two friends is in the ratio 6:5.the sum of their ages is 66.after how many years will the ages be in the ratio 8:7?

• Ans: 12 yrs
  
  let friends a,b in the ratio a:b=6:5 and a+b=66
  so, let x be the factor for ratio, then 6x+5x=66 ==> x=6
  so, the present ages of a,b are 36,30
  
  let after 'y' yrs they are in the ratio of 8:7
  so,(36+y):(30+y) = 8:7
  by solving we get y= 12
• 10 years agoHelpfull: Yes(20) No(0)
• Let there age be in ratio 6x & 5x. Sum is 66.
  so 6x+5x= 66.
  x= 6
  age 8x= 48,7x= 42.
  6x= 36,5x= 30.
  diff is 12 year.
  ans = 12 year
• 10 years agoHelpfull: Yes(4) No(0)
• Ans:12 yrs
  x:y=6:5,x+y=66
  i.e
  x=6/11(66)=36
  y=5/11(66)=30
  adding 12 years to both x=48,y=42
  The ratio becomes 8:7
• 10 years agoHelpfull: Yes(1) No(2)
• present ages are in the ratio of 6:5 .
  let me take they are 6x and 5x respectively.
  so 6x+5x=66.
  x=6 .
  new ratio is given as 8:7 i.e,each part is increased by 2. 6 becomes 8 and 5 becomes 7;one part is 6 so 2 parts is 2*6=12 .
  answer is 12.
• 10 years agoHelpfull: Yes(1) No(0)
• 12 36:30 = 6 :5 and 48:42=8:7
• 10 years agoHelpfull: Yes(1) No(0)
• let 6x+5x=66 then 11x=66=> x=66/11=6
  one age is 6x6=36,another one is 5x6=30
  lly the probabileity to have 8:7 ratio is 36+y/30+y=8/7=>
  252+7y=240y+8y then y=12 years
• 10 years agoHelpfull: Yes(0) No(0)
• After 12 years
• 10 years agoHelpfull: Yes(0) No(0)
• 2 friends age will be 6x,5x respectively
  sum of their age is 66
  6x+5x=66
  x=6 after 12 years
  48:42
  8:7
• 10 years agoHelpfull: Yes(0) No(0)
• Let their ages be 6x and 5x respectively
  6x+5x=66
  x=6
  so 6x=36
  & 5x=30
  36+x :30+x= 8:7
  hence x=12 Ans
• 10 years agoHelpfull: Yes(0) No(0)
• giusdhiagyudgashd
  
• 9 years agoHelpfull: Yes(0) No(0)