x 2-y 2 16 and 2 xy 4 so find out x y tell that both statement are required to

Both statement required.
10 years agoHelpfull: Yes(7) No(3)
both the statements are required.by substituting y=(4/x) from 2nd statement in 1st we can find the value of x and from that y and finally we get x+y.
10 years agoHelpfull: Yes(7) No(4)
Only second is require for calculating x+y
simple calculation:::
(x-y)^2=0
x^2-2xy+y^2=0
x^2-2xy+y^2+4xy-4xy=0 (add and substract 4xy)
x^2+2xy+y^2-4xy=0
x^2+2xy+y^2=4xy
(x+y)^2=4(4) (only xy is require here)
(x+y)=4
10 years agoHelpfull: Yes(5) No(10)
Only one statement is required
10 years agoHelpfull: Yes(4) No(3)
mr. sanjit guin.. please learn basic algebra formulae.
10 years agoHelpfull: Yes(3) No(0)
sorry about prev ans.
10 years agoHelpfull: Yes(2) No(0)
both statements are required to calculate x+y
(x+y)^2=x^2+y^2+2xy
or (X+Y)(X-Y)
10 years agoHelpfull: Yes(1) No(0)
(x^2)-(y^2)=(x+y)^2 - 2.xy also then, (x+y)^2 - 2.xy = 16 => (x+y)^2 = 16+4 => (x+y)=sqrt(20)
10 years agoHelpfull: Yes(1) No(14)
both statement required.....
10 years agoHelpfull: Yes(0) No(0)
given x^2-y^2=16 and xy=4 then x+y=?
let us consider xy=4,
x=4/y----1 and y=4/x------2 (sub 1 and 2 in the above eqn)
we get X^2+Y^2=1 then X^2+Y^2+2XY-2XY=1 ==> (X^2+Y^2+2XY)-2XY=1
(X+Y)^2=1+2XY ==>X+Y = sqrt of (1+2XY).
9 years agoHelpfull: Yes(0) No(0)

) x^2-y^2= 16 and 2. xy=4 so find out x+y=? tell that both statement are required to find out the value of x+Y