TCS
Company
Numerical Ability
Algebra
A Turtle is crossing a field.What is the total distance(in m) passed by turtle?Consider the following two statements.
(X)The avg speed of turtle is 2 mtre per min
(Y)Had the turtle walked 1 metre per min faster than his avg speed it would have finished the same path in 40 mins earlier
(a)St. Y alone is enough to get ans
(b)Both st X & Y are needed to get ans
(c)St. X & Y are together not enough to get answer
(d)St. X alone is enough to get answer.
Read Solution (Total 2)
-
- as distance is constant so
s1/s2= t2/t1
2/3=t/t+40
solve for t=80
so d=s*t
d=80*3
d=240 m
so both the statements are needed. - 10 years agoHelpfull: Yes(8) No(0)
- s=d/t=2 , 3=d/(t-40) from solving these both we get t=120 nd d=240m
- 10 years agoHelpfull: Yes(0) No(0)
TCS Other Question