there are two boxes.one containing 32 red balls and other containing 31green balls.you are
allowed to move the balls between the boxes so that when you choose a box at random and a ball
at random from the chosen box ,the probability of getting a red ball is maximized.the
maximum probability is
a.0.25
b.0.51
c.0.75
d.0.50

• Move 31 balls from red ball box to other box having 31 green balls.
  
  now one box has one red ball
  and
  other box is having 31 red balls and 31 green balls.
  
  then prob of getting red ball = 1/2 (1+31/62) = 1/2 *3/2 =3/4
• 13 years agoHelpfull: Yes(32) No(2)
• probability of choosing one(red) box is 1/2.
  Move 31 balls from red ball box to other box having 31 green balls.
  
  now one box has one red ball and other box is having 31 red balls and 31 green balls.
  
  then prob of getting red ball = (1/2)+(1/2)*(31/62) = 1/2 + 1/4 =3/4
• 13 years agoHelpfull: Yes(17) No(1)