17 How many number x x being integer with 10 lt x lt 99 are 18 more than sum of

2 digit no. = sum of their digits +18
10a+b = a+b +18
9a=18
a=2
=>first digit = 2
no. s starting with 2 and less than 99 and greater than 10
are 20 to 29 which are 10 in count so ans is 10.
8 years agoHelpfull: Yes(27) No(0)
well when the range 11-19 is subtracted from its sum of its digits its always 9
so for 11-19 difference is 9 (3*3)
for 20-29 difference is 18(3*6)
for 30-39 difference is 27(3*9)
n so on
so 10 is the answer
10 years agoHelpfull: Yes(12) No(2)
can anybody xpln it clearly
10 years agoHelpfull: Yes(4) No(4)
Let the no be xy.
a/q:- 10 x+y-(x+y)=18
9x=18
x=2
so we got here as 2y as the digit.
So it can be from 20 to 29.
So it can take 10 values.
8 years agoHelpfull: Yes(1) No(1)
ans 61
max.value of x can be 71(2+18>99)
and x varies from 10 to 99
so,71-10=61
10 years agoHelpfull: Yes(0) No(15)
10 is the answer
10 years agoHelpfull: Yes(0) No(0)
1010x+y=(x+y)+18only the numbers from 20-29 satisfies it.hence 10 numbers
8 years agoHelpfull: Yes(0) No(0)
can anyone say y u are taking 10 x+y or 10 a +b in L.H.S
7 years agoHelpfull: Yes(0) No(0)
anyone explain the question....
6 years agoHelpfull: Yes(0) No(0)
(x+y)+18=(10*x)+y
9*x=18
x=2 ; 2y is the number
numbers with tenth digit as 2 is 20-29 ans is:10
5 years agoHelpfull: Yes(0) No(0)

17. How many number x(x being integer) with 10<=x<=99 are 18 more than sum of their digits?
a. 12
b. 9
c. 18
d. 10