If N is a integer and N<2 at most how many integers N+2,N+3,N+4,N+5,N+6 & N+7 are prime integers?

• "Atmost":SO maximum no
  Take n=1=>3,4,5,6,7,8=>Primes=>3,5,7
  Take n=-1=>1,2,3,4,5,6=>primes=>3,5
  Take n=0=>2,3,4,5,6,7=>Primes=>2,3,5,7.So answer is 4 ( Zero is also a integer)
• 10 years agoHelpfull: Yes(32) No(0)
• 3
  taking n=1,
  so no,formed will be 3,4,5,6,7,8
  so no of prime no will be 3
  Ans: 3
• 10 years agoHelpfull: Yes(3) No(6)
• we take n=1
  then required integers are 3,4,5,6,7,8,in these nos,3,5 and 7 are prime integers.
  hence no of prime integers are 3
• 10 years agoHelpfull: Yes(1) No(4)
• can u xpln it clearly? plzzzzz
• 10 years agoHelpfull: Yes(1) No(0)
• 1.If N is an integer and N
• 10 years agoHelpfull: Yes(1) No(0)
• answer=2.
  let N=3,then 3+2,3+3,3+4,3+5,3+6,3+7=5,6,7,8,9,10=prime numbers=2
  
  
• 10 years agoHelpfull: Yes(0) No(13)
• whether n is odd or even both the time there will be only 2 prime integers
  n=3 only 5 & 7
  when n=4 only 7 & 11
  so 2 is the answer
• 10 years agoHelpfull: Yes(0) No(7)
• here n>2 not n
• 10 years agoHelpfull: Yes(0) No(2)
• i think ques is wrong ...N>2
  then ans is 2
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• given n
• 10 years agoHelpfull: Yes(0) No(0)
• N
• 10 years agoHelpfull: Yes(0) No(0)
• Since N is an integer, N=1,0,-1,-2,.... (N N+7=2 ==> Prime integer count=1
  
  now assume N= -4 ==> N+7=3, N+6=2 ==> Prime integer count=2
  
  now assume N= -3 ==> N+6=3, N+5=2 ==> Prime integer count=2
  
  now assume N= -2 ==> N+7=5, N+5=3, N+4=2 ==> Prime integer count=3
  
  now assume N= -1 ==> N+6=5, N+4=3, N+3=2 ==> Prime integer count=3
  
  now assume N= 0 ==> N+7=7, N+5=5, N+3=3, N+2=2 ==> Prime integer count=4
  
  now assume N= 1 ==> N+6=7, N+4=5, N+2=3 ==> Prime integer count=3
  
  TOTAL NUMBER OF PRIME INTEGERS= 1+2+2+3+3+4+3=18
• 10 years agoHelpfull: Yes(0) No(2)