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A goat is tied to one corner of a square plot of side 12m by a rope 7m long. Find the area it can graze?
(a) 38.5 sq.m
(b) 155 sq.m
(c) 144 sq.m
(d) 19.25 sq.m
PLEASE EXPLAIN ALSO..
Read Solution (Total 16)
-
- 38.5 sq m
Area covered by goat = Pi*r^2/4
whre r= 7 m = length of rope
so area = (22/7)*7*7/4 = 38.5 sq m - 13 years agoHelpfull: Yes(41) No(6)
- @ Vinay,
Because the goat is tied to a corner of square plot.
It can only graze in 1/4 th of circle of radius equal to lrngth of rope inside that square plot.
I agree with Dipin. - 13 years agoHelpfull: Yes(13) No(2)
- ACTUALLY I SOLVED THE PROBLEM BT THANKS TO DIPIN A LOT..........
- 13 years agoHelpfull: Yes(8) No(4)
- y divided by 4...plz expln
- 13 years agoHelpfull: Yes(8) No(3)
- Area covered is 1/4 th of a circle
Its radius is 7
hence area of circle=pi*r*r
Area covered by goat=(pi*r*r)/4
So area=((22/7)*7*7)/4)=38.5 sq.m - 10 years agoHelpfull: Yes(4) No(1)
- actually area of square is a^2 but why we are using area of circle?
- 11 years agoHelpfull: Yes(3) No(2)
- ((22/7)*49)/4=38.5
- 10 years agoHelpfull: Yes(2) No(2)
- formula :a/360*(pi*r*r) where a is angle made by rope when tied to a corner of square
90/360*22/7*7*7=38.5m^2 - 10 years agoHelpfull: Yes(2) No(2)
- 38.5, (90/360)(22/7)*7*7
- 9 years agoHelpfull: Yes(0) No(0)
- 38.5 sq m
Area covered=(pi*r^2)/4
r=7 - 9 years agoHelpfull: Yes(0) No(0)
- sise of square=12
rope size=7
area graze by goat=3.14*7*7/4=38.5 - 9 years agoHelpfull: Yes(0) No(0)
- so basically we have to find the area of the circle whose diameter is the length of the rope = 7m
Therefore radius = 7/2 = 3.5m
therefore area of the circle = Pi * (radius)^2 = Pi * (radius) * (radius) = 3.14 * 3.5 *3.5 = 38.5 sq.m - 9 years agoHelpfull: Yes(0) No(0)
- since length of rope=7m
so it can graze only area covered by radius 7m./4
since,within this square only 1/4th area is present
so....area=22/7*7*7/4
=38.5 m2 - 9 years agoHelpfull: Yes(0) No(0)
- a.38.5sq.m
(pi*r^2)/4
38.5
- 9 years agoHelpfull: Yes(0) No(0)
- area=pi*r*r/4
=3.142*7*7/4
=38.5 sqm - 9 years agoHelpfull: Yes(0) No(0)
- Why can't it grace outside the plot as in rectangular barn problems..............?
- 9 years agoHelpfull: Yes(0) No(0)
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