3,4,7,10,13,16,19,22,find 10th term in series

• 3
  3*1=3+1=4
  3*2=6+1=7
  3*3=9+1=10
  3*4=12+1=13
  3*5=15+1=16
  3*6=18+1=19
  3*7=21+1=22
  3*8=24+1=25
  3*9=27+1=28
  
  10th term = 28
• 10 years agoHelpfull: Yes(21) No(1)
• n+3=22+3+3=28
• 10 years agoHelpfull: Yes(18) No(1)
• 29
  alternate prime no.s--->> 1st no. alternate && +6 diff. in alternate no.s starting frm 2nd no.
• 10 years agoHelpfull: Yes(7) No(0)
• 3+4= 7
  3+7 =10
  3+10 = 13
  3+13 = 16
  3+16 = 19
  3+19 = 22
  3+22 = 25
  
  hence the series 3, 4, 7, 10, 13, 16, 19, 22, 25
• 10 years agoHelpfull: Yes(3) No(1)
• Was 34 an option? if it was in the options, den i gues, 34 is d ans.
  1st term -> 3 (could not gues the logic for 3 being the 1st term)
  
  2nd term -> 4=3*[1]+1 (1 is an ODD number)
  
  3rd term -> 7=3*[2]+1 (2 is an EVEN number)
  
  4th term -> 10=3*[3]+1 (3 is an ODD & PRIME number)
  
  5th term -> 13=3*[4]+1 (4 is an EVEN number)
  
  6th term -> 16=3*[5]+1 (5 is an ODD & PRIME number)
  
  7th term -> 19=3*[6]+1 (6 is an EVEN number)
  
  8th term -> 22=3*[7]+1 (7 is ODD & PRIME number)
  
  9th term -> 25=3*[8]+1 (8 is an EVEN number)
  
  10th term -> either 28=3*[9]+1 (9 is the next ODD number)
  or 34=3*[11]+1 (11 is the next ODD & PRIME number)
  Now its up to you, whether to place 9 or 11 in [ ]. If you place 9, den the ans. is 28 which was not in the options and if you place 11, den you have to consider that 1 is an ODD & PRIME number while calculating the 2nd term.
• 10 years agoHelpfull: Yes(2) No(1)
• 4+6=10
  10+6=16
  16+6=22
  22+6=28
  ANS====28
• 10 years agoHelpfull: Yes(2) No(0)
• Here is another way....
  all has prime number but alternate substraction by 1
  3
  5-1=4
  7
  11-1=10
  13
  17-1=16
  19
  23-1=22
  29
  31-1=30
  So by this method... the answer is 30.
• 6 years agoHelpfull: Yes(2) No(0)
• but 28 was not on the options
  nearest was 30 and 31??
  
• 10 years agoHelpfull: Yes(1) No(0)
• 10th term is 28
• 10 years agoHelpfull: Yes(1) No(0)
• 9th term is 29 by skipping prime numbers.
  10th term is 32.
• 10 years agoHelpfull: Yes(1) No(0)
• ans will be 30
  
• 10 years agoHelpfull: Yes(0) No(1)
• 25 is the answer....
  7-4=3
  10-7=3
  .....
  .....
  22-3=19
  22+3=25
  ie 35-3=22
• 10 years agoHelpfull: Yes(0) No(2)
• 23
  As Series starts with prime number and then a even number and so on... prime number just next to 19 is 23 and hence the answer.
  
• 10 years agoHelpfull: Yes(0) No(1)
• 31 by skipping next prime number and adding three
• 10 years agoHelpfull: Yes(0) No(0)
• 3*1+0=3
  3*1+1=4
  3*2+1=7
  3*3+1=10
  3*4+1=13
  3*5+1=16
  3*6+1=19
  3*7+1=22
  3*8+1=25
  so 25 is the answer
• 10 years agoHelpfull: Yes(0) No(5)
• Sum of left most digit and right most digit=next digit on right side
  3+4=7
  3+7=10
  3+10=13
  3+13=16
  3+16=19
  3+19=22
  3+22=25
  3+25=28 --> 10th term
• 10 years agoHelpfull: Yes(0) No(1)
• 3*1+1
  3*2+1
  3*3+1
  3*4+1
  in this way we have to proceed
  and last
  3*8+1
  ans is 25
• 10 years agoHelpfull: Yes(0) No(1)
• 3*1+1
  3*2+1
  3*3+1
  3*4+1
  in this way we hv to proceed
  and last
  3*10+1
  ans is 31
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 28
  3+4 =7
  3+7=10
  3+10=13
  3+13=16
  3+16=19
  3+19=22
  3+22=25
  3+25=28
  3+28=31
  3+31=34
• 10 years agoHelpfull: Yes(0) No(0)
• 58.........
• 9 years agoHelpfull: Yes(0) No(1)
• The series is in Arithmatic progression for 8th term
  
  t8=a+(n-1)d
  
  a=3
  n=8
  d=3
  
  sub we get t8=28
• 7 years agoHelpfull: Yes(0) No(0)
• 61..
  this is answer
• 7 years agoHelpfull: Yes(0) No(0)
• 3+1=4
  4+3=7
  7+3=10
  .
  
  28+3=31
• 7 years agoHelpfull: Yes(0) No(0)
• if we observe carefully we can split the series into two parts
  first part is alternate prime numbers ----- 3,7,13,19
  second part is increasing even values with a value of 6 ------4,10,16,22
  in the given series the last number is 22,so the next number in the series would be alternate prime number after 19 i.e., 29
  so the answer is 29
• 6 years agoHelpfull: Yes(0) No(0)
• Question : 3,4,7,10,13,16,19,22,___,____,....find 10th term in the series
  Solution : (1) Prime Number are : 2,3,5,7,11,13,17,19,23,29,....in this series they took the alternate
  numbers like 3,7,13,19,29,... so here the 9th term will be 29,..
  (2) remaining numbers in the questions are 4,10,16,22,.... so here
  2x2=4,2x5=10,2x8=16,2x11=22,...here they left 2x3=6,2x4=8, then they include again
  2x5=10 again they left number 12,14,...so on,...so at last the answer will be 28,...
  Answer :3,4,7,10,13,16,19,22,29,28,...here the 10th term is 28 ,.
• 5 years agoHelpfull: Yes(0) No(0)