A train goes from stations A to B. One day there is a technical problem at the very beginning of the journey & hence the train travels at 3/5 of it's original speed and so it arrives 2 hours late. Had the problem occured after 50 miles had been covered, the train would have arrived 40 min earlier(i.e., only 120-40 = 80 min late). What is the distance between the 2 stations?

• It the problem occurs at the start, delay=120mins
  It the problem occurs at 50miles from start, delay=120-40=80mins
  similarly when the problem would occur at 150miles from the delay=0
  thats because the train is already at the destination.. ;)
• 10 years agoHelpfull: Yes(24) No(14)
• s1:s2=5:3
  t1:t2=3:5
  diffrence in time=2 hours
  original time=3 hours
  Indirectly, in this train has travelled 50 miles in 40 minutes.
  so in 3 hours =225 miles which is the distance between A and B
• 10 years agoHelpfull: Yes(18) No(9)
• Indirectly,the train travels 50 miles in 40 minutes with it's original speed.
  so,original speed=60*50/40=75miles/hr
  let,distance=x and time taken with original speed=t hours
  
  so,75*t=x
  and (75*3/5)*(t+2)=x
  
  solving,.. x=225 miles
• 10 years agoHelpfull: Yes(14) No(2)
• t=180 minute ,d=150 miles.
• 10 years agoHelpfull: Yes(11) No(1)
• For 50 miles distance delay is 40 min.so for 1 mile distance delay is 4/5 min or we can say delay is 1 min for every 5/4 miles.
  hence,for 120 minutes delay it has to travel =120 x 5/4 =150 miles
• 8 years agoHelpfull: Yes(4) No(0)
• how 300 miles....can u explain in detail??
• 10 years agoHelpfull: Yes(2) No(3)
• 300 miles...
• 10 years agoHelpfull: Yes(1) No(5)
• 300 miles
  
• 10 years agoHelpfull: Yes(1) No(1)
• total distance=150 miles
  original speed=50 miles/hr
• 10 years agoHelpfull: Yes(1) No(0)
• Initial speed:x;after glitch:3x/5;basically we ought to consider the 1st 50 miles coz the rest cancels out while equating both cases;so-by problem,50/(3x/5)-50/x=40.on equating we get x=10/12;so now we have x,again,putting x=10/12 we have 50/10/11=60mins ;60 mins for 50 miles-one part done now distance,from the problem we can formulate:10/12*t=10/12*(3/5)*(t+120);we get t=180 so 60 mins for 50 miles;180mins=150 miles...
• 9 years agoHelpfull: Yes(1) No(1)
• The train travels 50 miles in 40 min
  So it travels 50 miles at its original speed in that 40 minutes that means
  Total distance is 120/3= 40
  50*3= 150
• 7 years agoHelpfull: Yes(1) No(1)
• 100 miles....
• 10 years agoHelpfull: Yes(0) No(5)
• 40 min earlier means it has covered this in its original speed..i.e. speed=40*2/3=75.
  now we have original time t and it covers at 3/5 of its original speed so time it will tak i.e. t2=5/3t.
  so t2-t1=2.from here t=3hrs.
  so speed=75 nad t=3hrs distance=75*3=225 mles
  
• 9 years agoHelpfull: Yes(0) No(2)